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0.03x^2-30x+4800=0
a = 0.03; b = -30; c = +4800;
Δ = b2-4ac
Δ = -302-4·0.03·4800
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-18}{2*0.03}=\frac{12}{0.06} =200 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+18}{2*0.03}=\frac{48}{0.06} =800 $
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